Base | Representation |
---|---|
bin | 110100100010111101… |
… | …111101100010010111 |
3 | 12101122002112010002211 |
4 | 310202331331202113 |
5 | 1411022314234111 |
6 | 41530343014251 |
7 | 4035112436626 |
oct | 644275754227 |
9 | 171562463084 |
10 | 56421243031 |
11 | 21a23358a7a |
12 | ab2743a387 |
13 | 54221a720a |
14 | 2a334736bd |
15 | 170348a521 |
hex | d22f7d897 |
56421243031 has 2 divisors, whose sum is σ = 56421243032. Its totient is φ = 56421243030.
The previous prime is 56421243017. The next prime is 56421243037. The reversal of 56421243031 is 13034212465.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56421243031 - 217 = 56421111959 is a prime.
It is a super-2 number, since 2×564212430312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 56421242984 and 56421243002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56421243037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28210621515 + 28210621516.
It is an arithmetic number, because the mean of its divisors is an integer number (28210621516).
Almost surely, 256421243031 is an apocalyptic number.
56421243031 is a deficient number, since it is larger than the sum of its proper divisors (1).
56421243031 is an equidigital number, since it uses as much as digits as its factorization.
56421243031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 56421243031 its reverse (13034212465), we get a palindrome (69455455496).
The spelling of 56421243031 in words is "fifty-six billion, four hundred twenty-one million, two hundred forty-three thousand, thirty-one".
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