Base | Representation |
---|---|
bin | 101001000011011110010… |
… | …0000001100000000100011 |
3 | 201222102011100211000212102 |
4 | 1102012330200030000203 |
5 | 1214421221340122201 |
6 | 20000035144321015 |
7 | 1121440166610143 |
oct | 122067440140043 |
9 | 21872140730772 |
10 | 5642454614051 |
11 | 1885a51592a52 |
12 | 77166677316b |
13 | 31c1094a2278 |
14 | 15714c1d2923 |
15 | 9bb8e7d926b |
hex | 521bc80c023 |
5642454614051 has 2 divisors, whose sum is σ = 5642454614052. Its totient is φ = 5642454614050.
The previous prime is 5642454614047. The next prime is 5642454614129. The reversal of 5642454614051 is 1504164542465.
5642454614051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5642454614051 - 22 = 5642454614047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5642454613987 and 5642454614005.
It is not a weakly prime, because it can be changed into another prime (5642454619051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2821227307025 + 2821227307026.
It is an arithmetic number, because the mean of its divisors is an integer number (2821227307026).
Almost surely, 25642454614051 is an apocalyptic number.
5642454614051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5642454614051 is an equidigital number, since it uses as much as digits as its factorization.
5642454614051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304000, while the sum is 47.
The spelling of 5642454614051 in words is "five trillion, six hundred forty-two billion, four hundred fifty-four million, six hundred fourteen thousand, fifty-one".
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