Base | Representation |
---|---|
bin | 110100100100010101… |
… | …100100101111000001 |
3 | 12101200200201222000111 |
4 | 310210111210233001 |
5 | 1411044204210423 |
6 | 41532523151321 |
7 | 4035511604224 |
oct | 644425445701 |
9 | 171620658014 |
10 | 56444210113 |
11 | 21a35315535 |
12 | ab33075541 |
13 | 5426b88cc5 |
14 | 2a365315bb |
15 | 17054c560d |
hex | d24564bc1 |
56444210113 has 2 divisors, whose sum is σ = 56444210114. Its totient is φ = 56444210112.
The previous prime is 56444210111. The next prime is 56444210131. The reversal of 56444210113 is 31101244465.
Together with next prime (56444210131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52616560689 + 3827649424 = 229383^2 + 61868^2 .
It is a cyclic number.
It is not a de Polignac number, because 56444210113 - 21 = 56444210111 is a prime.
Together with 56444210111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (56444210111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28222105056 + 28222105057.
It is an arithmetic number, because the mean of its divisors is an integer number (28222105057).
Almost surely, 256444210113 is an apocalyptic number.
It is an amenable number.
56444210113 is a deficient number, since it is larger than the sum of its proper divisors (1).
56444210113 is an equidigital number, since it uses as much as digits as its factorization.
56444210113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 56444210113 its reverse (31101244465), we get a palindrome (87545454578).
The spelling of 56444210113 in words is "fifty-six billion, four hundred forty-four million, two hundred ten thousand, one hundred thirteen".
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