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56485201207 is a prime number
BaseRepresentation
bin110100100110110001…
…111100010100110111
312101210112212112020011
4310212301330110313
51411140202414312
641540545521051
74036520200621
oct644661742467
9171715775204
1056485201207
1121a56472776
12ab44943187
13543250b9a6
142a3bb61c11
151708dc0da7
hexd26c7c537

56485201207 has 2 divisors, whose sum is σ = 56485201208. Its totient is φ = 56485201206.

The previous prime is 56485201159. The next prime is 56485201217. The reversal of 56485201207 is 70210258465.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56485201207 is a prime.

It is a super-3 number, since 3×564852012073 (a number of 33 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 56485201207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56485201217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28242600603 + 28242600604.

It is an arithmetic number, because the mean of its divisors is an integer number (28242600604).

Almost surely, 256485201207 is an apocalyptic number.

56485201207 is a deficient number, since it is larger than the sum of its proper divisors (1).

56485201207 is an equidigital number, since it uses as much as digits as its factorization.

56485201207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 134400, while the sum is 40.

The spelling of 56485201207 in words is "fifty-six billion, four hundred eighty-five million, two hundred one thousand, two hundred seven".