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56490113341 is a prime number
BaseRepresentation
bin110100100111000100…
…101011100100111101
312101210220010002102001
4310213010223210331
51411142432111331
641541243102301
74036610016664
oct644704534475
9171726102361
1056490113341
1121a59218292
12ab46511991
13543353b78c
142a3c67dddb
151709541561
hexd2712b93d

56490113341 has 2 divisors, whose sum is σ = 56490113342. Its totient is φ = 56490113340.

The previous prime is 56490113311. The next prime is 56490113411. The reversal of 56490113341 is 14331109465.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31511575225 + 24978538116 = 177515^2 + 158046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56490113341 is a prime.

It is a super-2 number, since 2×564901133412 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 56490113341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56490113311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28245056670 + 28245056671.

It is an arithmetic number, because the mean of its divisors is an integer number (28245056671).

Almost surely, 256490113341 is an apocalyptic number.

It is an amenable number.

56490113341 is a deficient number, since it is larger than the sum of its proper divisors (1).

56490113341 is an equidigital number, since it uses as much as digits as its factorization.

56490113341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 56490113341 in words is "fifty-six billion, four hundred ninety million, one hundred thirteen thousand, three hundred forty-one".