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56580130237 is a prime number
BaseRepresentation
bin110100101100011100…
…000100010110111101
312102001011111102101011
4310230130010112331
51411334003131422
641554220315221
74042052112631
oct645434042675
9172034442334
1056580130237
1121aa5010314
12ab706a2b11
135449098307
142a4a5d2dc1
1517123c3077
hexd2c7045bd

56580130237 has 2 divisors, whose sum is σ = 56580130238. Its totient is φ = 56580130236.

The previous prime is 56580130219. The next prime is 56580130291. The reversal of 56580130237 is 73203108565.

56580130237 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54372446041 + 2207684196 = 233179^2 + 46986^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56580130237 is a prime.

It is a super-2 number, since 2×565801302372 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 56580130237.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56580130207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28290065118 + 28290065119.

It is an arithmetic number, because the mean of its divisors is an integer number (28290065119).

Almost surely, 256580130237 is an apocalyptic number.

It is an amenable number.

56580130237 is a deficient number, since it is larger than the sum of its proper divisors (1).

56580130237 is an equidigital number, since it uses as much as digits as its factorization.

56580130237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 40.

The spelling of 56580130237 in words is "fifty-six billion, five hundred eighty million, one hundred thirty thousand, two hundred thirty-seven".