Base | Representation |
---|---|
bin | 101001001110011100010… |
… | …0110100101011111010111 |
3 | 202001122222002020221212021 |
4 | 1102130320212211133113 |
5 | 1220312442421040201 |
6 | 20014532454234011 |
7 | 1123233022061311 |
oct | 122347046453727 |
9 | 22048862227767 |
10 | 5666011502551 |
11 | 1894a3a864a44 |
12 | 77613b955907 |
13 | 3213c1a4414a |
14 | 158344a447b1 |
15 | 9c5bc94cea1 |
hex | 527389a57d7 |
5666011502551 has 2 divisors, whose sum is σ = 5666011502552. Its totient is φ = 5666011502550.
The previous prime is 5666011502533. The next prime is 5666011502579. The reversal of 5666011502551 is 1552051106665.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5666011502551 - 25 = 5666011502519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5666011502498 and 5666011502507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5666011502051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2833005751275 + 2833005751276.
It is an arithmetic number, because the mean of its divisors is an integer number (2833005751276).
Almost surely, 25666011502551 is an apocalyptic number.
5666011502551 is a deficient number, since it is larger than the sum of its proper divisors (1).
5666011502551 is an equidigital number, since it uses as much as digits as its factorization.
5666011502551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270000, while the sum is 43.
The spelling of 5666011502551 in words is "five trillion, six hundred sixty-six billion, eleven million, five hundred two thousand, five hundred fifty-one".
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