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5666601715937 is a prime number
BaseRepresentation
bin101001001110101101111…
…0010000100100011100001
3202001201111012211220102022
41102131123302010203201
51220320200014402222
620015111220431225
71123253446600121
oct122353362044341
922051435756368
105666601715937
111895212a38aa8
12776285548515
133214870c4336
1415839d1a0c81
159c604686042
hex5275bc848e1

5666601715937 has 2 divisors, whose sum is σ = 5666601715938. Its totient is φ = 5666601715936.

The previous prime is 5666601715891. The next prime is 5666601715939. The reversal of 5666601715937 is 7395171066665.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3724344180736 + 1942257535201 = 1929856^2 + 1393649^2 .

It is a cyclic number.

It is not a de Polignac number, because 5666601715937 - 28 = 5666601715681 is a prime.

It is a super-2 number, since 2×56666017159372 (a number of 26 digits) contains 22 as substring.

Together with 5666601715939, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5666601715937.

It is not a weakly prime, because it can be changed into another prime (5666601715939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2833300857968 + 2833300857969.

It is an arithmetic number, because the mean of its divisors is an integer number (2833300857969).

Almost surely, 25666601715937 is an apocalyptic number.

It is an amenable number.

5666601715937 is a deficient number, since it is larger than the sum of its proper divisors (1).

5666601715937 is an equidigital number, since it uses as much as digits as its factorization.

5666601715937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42865200, while the sum is 62.

The spelling of 5666601715937 in words is "five trillion, six hundred sixty-six billion, six hundred one million, seven hundred fifteen thousand, nine hundred thirty-seven".