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56700633253553 is a prime number
BaseRepresentation
bin11001110010001101001010…
…00110101000011010110001
321102202112020121202211100022
430321012211012220122301
524412440344103103203
6320331524502333225
714641325356344152
oct1471064506503261
9242675217684308
1056700633253553
111708067031a983
126438b6742a215
132583b0148c443
14100047a85d929
15684da858aa38
hex3391a51a86b1

56700633253553 has 2 divisors, whose sum is σ = 56700633253554. Its totient is φ = 56700633253552.

The previous prime is 56700633253519. The next prime is 56700633253643. The reversal of 56700633253553 is 35535233600765.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56666824341169 + 33808912384 = 7527737^2 + 183872^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56700633253553 is a prime.

It is a super-2 number, since 2×567006332535532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 56700633253495 and 56700633253504.

It is not a weakly prime, because it can be changed into another prime (56700633250553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28350316626776 + 28350316626777.

It is an arithmetic number, because the mean of its divisors is an integer number (28350316626777).

Almost surely, 256700633253553 is an apocalyptic number.

It is an amenable number.

56700633253553 is a deficient number, since it is larger than the sum of its proper divisors (1).

56700633253553 is an equidigital number, since it uses as much as digits as its factorization.

56700633253553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25515000, while the sum is 53.

The spelling of 56700633253553 in words is "fifty-six trillion, seven hundred billion, six hundred thirty-three million, two hundred fifty-three thousand, five hundred fifty-three".