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5670679153 is a prime number
BaseRepresentation
bin1010100011111111…
…11011001001110001
3112122012101100101211
411101333323021301
543103143213103
62334410200121
7260344656166
oct52177731161
915565340354
105670679153
11244aa501a7
121123123041
136c4aa3169
143bb1a606d
15232c8636d
hex151ffb271

5670679153 has 2 divisors, whose sum is σ = 5670679154. Its totient is φ = 5670679152.

The previous prime is 5670679129. The next prime is 5670679177. The reversal of 5670679153 is 3519760765.

It is a balanced prime because it is at equal distance from previous prime (5670679129) and next prime (5670679177).

It can be written as a sum of positive squares in only one way, i.e., 3300157809 + 2370521344 = 57447^2 + 48688^2 .

It is a cyclic number.

It is not a de Polignac number, because 5670679153 - 25 = 5670679121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5670679097 and 5670679106.

It is not a weakly prime, because it can be changed into another prime (5670679453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2835339576 + 2835339577.

It is an arithmetic number, because the mean of its divisors is an integer number (2835339577).

Almost surely, 25670679153 is an apocalyptic number.

It is an amenable number.

5670679153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5670679153 is an equidigital number, since it uses as much as digits as its factorization.

5670679153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1190700, while the sum is 49.

The square root of 5670679153 is about 75303.9119368974. The cubic root of 5670679153 is about 1783.2477793256.

The spelling of 5670679153 in words is "five billion, six hundred seventy million, six hundred seventy-nine thousand, one hundred fifty-three".