Base | Representation |
---|---|
bin | 101001010011100010010… |
… | …1100100011100011001111 |
3 | 202002201012112101021110202 |
4 | 1102213010230203203033 |
5 | 1221002344130443203 |
6 | 20023542231124115 |
7 | 1124101105140152 |
oct | 122470454434317 |
9 | 22081175337422 |
10 | 5676951812303 |
11 | 1899644333652 |
12 | 77829381363b |
13 | 32244649c805 |
14 | 158aa1a17c99 |
15 | 9ca0d14b388 |
hex | 529c4b238cf |
5676951812303 has 2 divisors, whose sum is σ = 5676951812304. Its totient is φ = 5676951812302.
The previous prime is 5676951812281. The next prime is 5676951812347. The reversal of 5676951812303 is 3032181596765.
5676951812303 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5676951812303 - 26 = 5676951812239 is a prime.
It is a super-2 number, since 2×56769518123032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5676951812393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2838475906151 + 2838475906152.
It is an arithmetic number, because the mean of its divisors is an integer number (2838475906152).
Almost surely, 25676951812303 is an apocalyptic number.
5676951812303 is a deficient number, since it is larger than the sum of its proper divisors (1).
5676951812303 is an equidigital number, since it uses as much as digits as its factorization.
5676951812303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8164800, while the sum is 56.
The spelling of 5676951812303 in words is "five trillion, six hundred seventy-six billion, nine hundred fifty-one million, eight hundred twelve thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •