Base | Representation |
---|---|
bin | 100001110111101… |
… | …101111010110011 |
3 | 1110121021022010022 |
4 | 201313231322303 |
5 | 2130433113011 |
6 | 132215354055 |
7 | 20040036404 |
oct | 4167557263 |
9 | 1417238108 |
10 | 568254131 |
11 | 271845815 |
12 | 13a38292b |
13 | 90962063 |
14 | 556819ab |
15 | 34d4b8db |
hex | 21dedeb3 |
568254131 has 2 divisors, whose sum is σ = 568254132. Its totient is φ = 568254130.
The previous prime is 568254107. The next prime is 568254133. The reversal of 568254131 is 131452865.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 568254131 - 26 = 568254067 is a prime.
It is a super-2 number, since 2×5682541312 = 645825514797130322, which contains 22 as substring.
Together with 568254133, it forms a pair of twin primes.
It is a Chen prime.
It is equal to p29751812 and since 568254131 and 29751812 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 568254091 and 568254100.
It is not a weakly prime, because it can be changed into another prime (568254133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 284127065 + 284127066.
It is an arithmetic number, because the mean of its divisors is an integer number (284127066).
Almost surely, 2568254131 is an apocalyptic number.
568254131 is a deficient number, since it is larger than the sum of its proper divisors (1).
568254131 is an equidigital number, since it uses as much as digits as its factorization.
568254131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 28800, while the sum is 35.
The square root of 568254131 is about 23838.0815293513. The cubic root of 568254131 is about 828.2870420507.
The spelling of 568254131 in words is "five hundred sixty-eight million, two hundred fifty-four thousand, one hundred thirty-one".
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