Base | Representation |
---|---|
bin | 101001011011010100110… |
… | …0110000111001000101111 |
3 | 202011022101010210012221021 |
4 | 1102312221212013020233 |
5 | 1221241122303214112 |
6 | 20035350014115011 |
7 | 1125232424016004 |
oct | 122665146071057 |
9 | 22138333705837 |
10 | 5693677007407 |
11 | 18a5747267244 |
12 | 77b580aaba67 |
13 | 323bb057706c |
14 | 15980b0018ab |
15 | 9d18b63e907 |
hex | 52da998722f |
5693677007407 has 2 divisors, whose sum is σ = 5693677007408. Its totient is φ = 5693677007406.
The previous prime is 5693677007401. The next prime is 5693677007437. The reversal of 5693677007407 is 7047007763965.
5693677007407 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5693677007407 - 23 = 5693677007399 is a prime.
It is a super-2 number, since 2×56936770074072 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5693677007401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2846838503703 + 2846838503704.
It is an arithmetic number, because the mean of its divisors is an integer number (2846838503704).
Almost surely, 25693677007407 is an apocalyptic number.
5693677007407 is a deficient number, since it is larger than the sum of its proper divisors (1).
5693677007407 is an equidigital number, since it uses as much as digits as its factorization.
5693677007407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46675440, while the sum is 61.
The spelling of 5693677007407 in words is "five trillion, six hundred ninety-three billion, six hundred seventy-seven million, seven thousand, four hundred seven".
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