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5693933 = 7813419
BaseRepresentation
bin10101101110000111101101
3101201021121102
4111232013231
52424201213
6322012445
766253250
oct25560755
911637542
105693933
113239a33
121aa7125
1312448bb
14a83097
15777158
hex56e1ed

5693933 has 4 divisors (see below), whose sum is σ = 6507360. Its totient is φ = 4880508.

The previous prime is 5693921. The next prime is 5693959. The reversal of 5693933 is 3393965.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5693933 - 24 = 5693917 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a plaindrome in base 13.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5693993) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406703 + ... + 406716.

It is an arithmetic number, because the mean of its divisors is an integer number (1626840).

Almost surely, 25693933 is an apocalyptic number.

It is an amenable number.

5693933 is a deficient number, since it is larger than the sum of its proper divisors (813427).

5693933 is an equidigital number, since it uses as much as digits as its factorization.

5693933 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 813426.

The product of its digits is 65610, while the sum is 38.

The square root of 5693933 is about 2386.1963456514. The cubic root of 5693933 is about 178.5681986159.

Subtracting from 5693933 its reverse (3393965), we obtain a cube (2299968 = 1323).

The spelling of 5693933 in words is "five million, six hundred ninety-three thousand, nine hundred thirty-three".

Divisors: 1 7 813419 5693933