Base | Representation |
---|---|
bin | 110101000010000100… |
… | …101010101001000111 |
3 | 12102222110110220112012 |
4 | 311002010222221013 |
5 | 1413104413004333 |
6 | 42054224044435 |
7 | 4054050213212 |
oct | 650204525107 |
9 | 172873426465 |
10 | 56943094343 |
11 | 2217098a653 |
12 | b05216371b |
13 | 54a6340285 |
14 | 2a828b6779 |
15 | 17341bce48 |
hex | d4212aa47 |
56943094343 has 2 divisors, whose sum is σ = 56943094344. Its totient is φ = 56943094342.
The previous prime is 56943094309. The next prime is 56943094381. The reversal of 56943094343 is 34349034965.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56943094343 is a prime.
It is an alternating number because its digits alternate between odd and even.
It is a junction number, because it is equal to n+sod(n) for n = 56943094291 and 56943094300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56943094303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28471547171 + 28471547172.
It is an arithmetic number, because the mean of its divisors is an integer number (28471547172).
Almost surely, 256943094343 is an apocalyptic number.
56943094343 is a deficient number, since it is larger than the sum of its proper divisors (1).
56943094343 is an equidigital number, since it uses as much as digits as its factorization.
56943094343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4199040, while the sum is 50.
The spelling of 56943094343 in words is "fifty-six billion, nine hundred forty-three million, ninety-four thousand, three hundred forty-three".
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