Base | Representation |
---|---|
bin | 1010101001000011… |
… | …10110000101000100 |
3 | 112202011020212010011 |
4 | 11110201312011010 |
5 | 43200030010300 |
6 | 2342524040004 |
7 | 261401524102 |
oct | 52441660504 |
9 | 15664225104 |
10 | 5713125700 |
11 | 2471a01997 |
12 | 1135393004 |
13 | 700815469 |
14 | 3c2a94c72 |
15 | 23686ceba |
hex | 154876144 |
5713125700 has 36 divisors (see below), whose sum is σ = 12431343232. Its totient is φ = 2279008800.
The previous prime is 5713125697. The next prime is 5713125703. The reversal of 5713125700 is 75213175.
It is an interprime number because it is at equal distance from previous prime (5713125697) and next prime (5713125703).
It is not an unprimeable number, because it can be changed into a prime (5713125703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 41136 + ... + 114535.
Almost surely, 25713125700 is an apocalyptic number.
5713125700 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5713125700 is an abundant number, since it is smaller than the sum of its proper divisors (6718217532).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5713125700 is a wasteful number, since it uses less digits than its factorization.
5713125700 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 156052 (or 156045 counting only the distinct ones).
The product of its (nonzero) digits is 7350, while the sum is 31.
The square root of 5713125700 is about 75585.2214391147. The cubic root of 5713125700 is about 1787.6860855711.
Adding to 5713125700 its reverse (75213175), we get a palindrome (5788338875).
The spelling of 5713125700 in words is "five billion, seven hundred thirteen million, one hundred twenty-five thousand, seven hundred".
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