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57145548253 is a prime number
BaseRepresentation
bin110101001110001000…
…111101110111011101
312110111120102122002011
4311032020331313131
51414013230021003
642130255231221
74062056100643
oct651610756735
9173446378064
1057145548253
1122265199232
12b0a9b18511
1355092764a1
142aa1737193
151746d5e46d
hexd4e23dddd

57145548253 has 2 divisors, whose sum is σ = 57145548254. Its totient is φ = 57145548252.

The previous prime is 57145548233. The next prime is 57145548259. The reversal of 57145548253 is 35284554175.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29390987844 + 27754560409 = 171438^2 + 166597^2 .

It is a cyclic number.

It is not a de Polignac number, because 57145548253 - 217 = 57145417181 is a prime.

It is a super-2 number, since 2×571455482532 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 57145548197 and 57145548206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57145548259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28572774126 + 28572774127.

It is an arithmetic number, because the mean of its divisors is an integer number (28572774127).

Almost surely, 257145548253 is an apocalyptic number.

It is an amenable number.

57145548253 is a deficient number, since it is larger than the sum of its proper divisors (1).

57145548253 is an equidigital number, since it uses as much as digits as its factorization.

57145548253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3360000, while the sum is 49.

The spelling of 57145548253 in words is "fifty-seven billion, one hundred forty-five million, five hundred forty-eight thousand, two hundred fifty-three".