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571520055553 is a prime number
BaseRepresentation
bin10000101000100010011…
…11111111100100000001
32000122012012210222022221
420110101033333210001
533330433113234203
61114315214131041
756201541214006
oct10242117774401
92018165728287
10571520055553
11200420198827
1292920ab0a81
1341b8148a185
141d939a7d8ad
15ecee900abd
hex85113ff901

571520055553 has 2 divisors, whose sum is σ = 571520055554. Its totient is φ = 571520055552.

The previous prime is 571520055551. The next prime is 571520055581. The reversal of 571520055553 is 355550025175.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 460705635009 + 110814420544 = 678753^2 + 332888^2 .

It is a cyclic number.

It is not a de Polignac number, because 571520055553 - 21 = 571520055551 is a prime.

It is a super-2 number, since 2×5715200555532 (a number of 24 digits) contains 22 as substring.

Together with 571520055551, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (571520055551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285760027776 + 285760027777.

It is an arithmetic number, because the mean of its divisors is an integer number (285760027777).

Almost surely, 2571520055553 is an apocalyptic number.

It is an amenable number.

571520055553 is a deficient number, since it is larger than the sum of its proper divisors (1).

571520055553 is an equidigital number, since it uses as much as digits as its factorization.

571520055553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 656250, while the sum is 43.

The spelling of 571520055553 in words is "five hundred seventy-one billion, five hundred twenty million, fifty-five thousand, five hundred fifty-three".