Base | Representation |
---|---|
bin | 101001100111100110010… |
… | …0111011000010100111111 |
3 | 202020211102000202202200011 |
4 | 1103033030213120110333 |
5 | 1222204112243040203 |
6 | 20055425243244051 |
7 | 1130154532502434 |
oct | 123171447302477 |
9 | 22224360682604 |
10 | 5720034346303 |
11 | 19059422a4052 |
12 | 7846b7b19627 |
13 | 326521073194 |
14 | 15abcb753b8b |
15 | 9dbd057b76d |
hex | 533cc9d853f |
5720034346303 has 2 divisors, whose sum is σ = 5720034346304. Its totient is φ = 5720034346302.
The previous prime is 5720034346267. The next prime is 5720034346307. The reversal of 5720034346303 is 3036434300275.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5720034346303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5720034346307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2860017173151 + 2860017173152.
It is an arithmetic number, because the mean of its divisors is an integer number (2860017173152).
Almost surely, 25720034346303 is an apocalyptic number.
5720034346303 is a deficient number, since it is larger than the sum of its proper divisors (1).
5720034346303 is an equidigital number, since it uses as much as digits as its factorization.
5720034346303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 40.
Adding to 5720034346303 its reverse (3036434300275), we get a palindrome (8756468646578).
The spelling of 5720034346303 in words is "five trillion, seven hundred twenty billion, thirty-four million, three hundred forty-six thousand, three hundred three".
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