Base | Representation |
---|---|
bin | 110101010110011111… |
… | …101011100110101011 |
3 | 12110212100012010020112 |
4 | 311112133223212223 |
5 | 1414310121023431 |
6 | 42152223444535 |
7 | 4065410406236 |
oct | 652637534653 |
9 | 173770163215 |
10 | 57285720491 |
11 | 2232732875a |
12 | b128a5674b |
13 | 552c31403c |
14 | 2ab61c441d |
15 | 17542ebc2b |
hex | d567eb9ab |
57285720491 has 2 divisors, whose sum is σ = 57285720492. Its totient is φ = 57285720490.
The previous prime is 57285720469. The next prime is 57285720493. The reversal of 57285720491 is 19402758275.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 57285720491 - 226 = 57218611627 is a prime.
Together with 57285720493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (57285720493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28642860245 + 28642860246.
It is an arithmetic number, because the mean of its divisors is an integer number (28642860246).
Almost surely, 257285720491 is an apocalyptic number.
57285720491 is a deficient number, since it is larger than the sum of its proper divisors (1).
57285720491 is an equidigital number, since it uses as much as digits as its factorization.
57285720491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1411200, while the sum is 50.
The spelling of 57285720491 in words is "fifty-seven billion, two hundred eighty-five million, seven hundred twenty thousand, four hundred ninety-one".
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