Base | Representation |
---|---|
bin | 11010000011111100011100… |
… | …11100110110110011010101 |
3 | 21111220210111002112110120101 |
4 | 31001332032130312303111 |
5 | 30002432130432402301 |
6 | 321515525244334101 |
7 | 15033343442100046 |
oct | 1501761634666325 |
9 | 244823432473511 |
10 | 57310138559701 |
11 | 17296103165695 |
12 | 6517109544331 |
13 | 25c942748c251 |
14 | 1021b7b2928cd |
15 | 695b7cb4a701 |
hex | 341f8e736cd5 |
57310138559701 has 2 divisors, whose sum is σ = 57310138559702. Its totient is φ = 57310138559700.
The previous prime is 57310138559657. The next prime is 57310138559719. The reversal of 57310138559701 is 10795583101375.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48494524367601 + 8815614192100 = 6963801^2 + 2969110^2 .
It is a cyclic number.
It is not a de Polignac number, because 57310138559701 - 231 = 57307991076053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (57310138559731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28655069279850 + 28655069279851.
It is an arithmetic number, because the mean of its divisors is an integer number (28655069279851).
Almost surely, 257310138559701 is an apocalyptic number.
It is an amenable number.
57310138559701 is a deficient number, since it is larger than the sum of its proper divisors (1).
57310138559701 is an equidigital number, since it uses as much as digits as its factorization.
57310138559701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3969000, while the sum is 55.
The spelling of 57310138559701 in words is "fifty-seven trillion, three hundred ten billion, one hundred thirty-eight million, five hundred fifty-nine thousand, seven hundred one".
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