Base | Representation |
---|---|
bin | 110101011001001101… |
… | …111110100011100001 |
3 | 12110222112011110001212 |
4 | 311121031332203201 |
5 | 1414403320124134 |
6 | 42200535035505 |
7 | 4066503645224 |
oct | 653115764341 |
9 | 173875143055 |
10 | 57331411169 |
11 | 223500a584a |
12 | b14020bb95 |
13 | 5538920b46 |
14 | 2abc2b95bb |
15 | 1758324bce |
hex | d5937e8e1 |
57331411169 has 2 divisors, whose sum is σ = 57331411170. Its totient is φ = 57331411168.
The previous prime is 57331411153. The next prime is 57331411211. The reversal of 57331411169 is 96111413375.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39486458944 + 17844952225 = 198712^2 + 133585^2 .
It is a cyclic number.
It is not a de Polignac number, because 57331411169 - 24 = 57331411153 is a prime.
It is a super-2 number, since 2×573314111692 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (57331413169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28665705584 + 28665705585.
It is an arithmetic number, because the mean of its divisors is an integer number (28665705585).
Almost surely, 257331411169 is an apocalyptic number.
It is an amenable number.
57331411169 is a deficient number, since it is larger than the sum of its proper divisors (1).
57331411169 is an equidigital number, since it uses as much as digits as its factorization.
57331411169 is an evil number, because the sum of its binary digits is even.
The product of its digits is 68040, while the sum is 41.
The spelling of 57331411169 in words is "fifty-seven billion, three hundred thirty-one million, four hundred eleven thousand, one hundred sixty-nine".
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