Base | Representation |
---|---|
bin | 110101011001001101… |
… | …111110100100001011 |
3 | 12110222112011110010102 |
4 | 311121031332210023 |
5 | 1414403320124321 |
6 | 42200535040015 |
7 | 4066503645314 |
oct | 653115764413 |
9 | 173875143112 |
10 | 57331411211 |
11 | 223500a5888 |
12 | b14021000b |
13 | 5538920b79 |
14 | 2abc2b960b |
15 | 1758324c0b |
hex | d5937e90b |
57331411211 has 2 divisors, whose sum is σ = 57331411212. Its totient is φ = 57331411210.
The previous prime is 57331411169. The next prime is 57331411217. The reversal of 57331411211 is 11211413375.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-57331411211 is a prime.
It is a super-2 number, since 2×573314112112 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (57331411217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28665705605 + 28665705606.
It is an arithmetic number, because the mean of its divisors is an integer number (28665705606).
Almost surely, 257331411211 is an apocalyptic number.
57331411211 is a deficient number, since it is larger than the sum of its proper divisors (1).
57331411211 is an equidigital number, since it uses as much as digits as its factorization.
57331411211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2520, while the sum is 29.
Adding to 57331411211 its reverse (11211413375), we get a palindrome (68542824586).
The spelling of 57331411211 in words is "fifty-seven billion, three hundred thirty-one million, four hundred eleven thousand, two hundred eleven".
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