Base | Representation |
---|---|
bin | 11010000110011001010011… |
… | …00000011100111010111111 |
3 | 21112012211211112120210101021 |
4 | 31003030221200130322333 |
5 | 30010322104123140000 |
6 | 322022333042525011 |
7 | 15042414233355115 |
oct | 1503145140347277 |
9 | 245184745523337 |
10 | 57394344349375 |
11 | 17318894132800 |
12 | 652b4a9966767 |
13 | 2604356a490b7 |
14 | 1025c8882dab5 |
15 | 697e5a48e11a |
hex | 34332981cebf |
57394344349375 has 30 divisors (see below), whose sum is σ = 78832697368040. Its totient is φ = 41741341290000.
The previous prime is 57394344349369. The next prime is 57394344349417.
57394344349375 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 57394344349375 - 23 = 57394344349367 is a prime.
It is a super-2 number, since 2×573943443493752 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 379391115 + ... + 379542364.
Almost surely, 257394344349375 is an apocalyptic number.
57394344349375 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
57394344349375 is a deficient number, since it is larger than the sum of its proper divisors (21438353018665).
57394344349375 is an equidigital number, since it uses as much as digits as its factorization.
57394344349375 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 758933521 (or 758933495 counting only the distinct ones).
The product of its digits is 2057529600, while the sum is 70.
The spelling of 57394344349375 in words is "fifty-seven trillion, three hundred ninety-four billion, three hundred forty-four million, three hundred forty-nine thousand, three hundred seventy-five".
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