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574941131881 is a prime number
BaseRepresentation
bin10000101110111010010…
…10010111010001101001
32000222000122011122210121
420113131022113101221
533404434412210011
61120042503443241
756352401662324
oct10273512272151
92028018148717
10574941131881
1120191630a036
1293516756521
13422a81822ac
141db821757bb
15ee4ee1ce71
hex85dd297469

574941131881 has 2 divisors, whose sum is σ = 574941131882. Its totient is φ = 574941131880.

The previous prime is 574941131879. The next prime is 574941131893. The reversal of 574941131881 is 188131149475.

574941131881 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 517415507856 + 57525624025 = 719316^2 + 239845^2 .

It is a cyclic number.

It is not a de Polignac number, because 574941131881 - 21 = 574941131879 is a prime.

It is a super-2 number, since 2×5749411318812 (a number of 24 digits) contains 22 as substring.

Together with 574941131879, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (574941131851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 287470565940 + 287470565941.

It is an arithmetic number, because the mean of its divisors is an integer number (287470565941).

Almost surely, 2574941131881 is an apocalyptic number.

It is an amenable number.

574941131881 is a deficient number, since it is larger than the sum of its proper divisors (1).

574941131881 is an equidigital number, since it uses as much as digits as its factorization.

574941131881 is an evil number, because the sum of its binary digits is even.

The product of its digits is 967680, while the sum is 52.

The spelling of 574941131881 in words is "five hundred seventy-four billion, nine hundred forty-one million, one hundred thirty-one thousand, eight hundred eighty-one".