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57516113121133 is a prime number
BaseRepresentation
bin11010001001111100000110…
…11111011100111101101101
321112122111010211000022120211
431010332003133130331231
530014320444424334013
6322154312042142421
715054254621012362
oct1504760337347555
9245574124008524
1057516113121133
11173654a0462267
12654b011ab1a11
13261299150b474
14102bb1aa40469
1569b1d588023d
hex344f837dcf6d

57516113121133 has 2 divisors, whose sum is σ = 57516113121134. Its totient is φ = 57516113121132.

The previous prime is 57516113121121. The next prime is 57516113121197. The reversal of 57516113121133 is 33112131161575.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56051245880644 + 1464867240489 = 7486738^2 + 1210317^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-57516113121133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57516113127133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28758056560566 + 28758056560567.

It is an arithmetic number, because the mean of its divisors is an integer number (28758056560567).

Almost surely, 257516113121133 is an apocalyptic number.

It is an amenable number.

57516113121133 is a deficient number, since it is larger than the sum of its proper divisors (1).

57516113121133 is an equidigital number, since it uses as much as digits as its factorization.

57516113121133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 56700, while the sum is 40.

The spelling of 57516113121133 in words is "fifty-seven trillion, five hundred sixteen billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred thirty-three".