Base | Representation |
---|---|
bin | 11010001001111100000110… |
… | …11111011100111101101101 |
3 | 21112122111010211000022120211 |
4 | 31010332003133130331231 |
5 | 30014320444424334013 |
6 | 322154312042142421 |
7 | 15054254621012362 |
oct | 1504760337347555 |
9 | 245574124008524 |
10 | 57516113121133 |
11 | 173654a0462267 |
12 | 654b011ab1a11 |
13 | 261299150b474 |
14 | 102bb1aa40469 |
15 | 69b1d588023d |
hex | 344f837dcf6d |
57516113121133 has 2 divisors, whose sum is σ = 57516113121134. Its totient is φ = 57516113121132.
The previous prime is 57516113121121. The next prime is 57516113121197. The reversal of 57516113121133 is 33112131161575.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 56051245880644 + 1464867240489 = 7486738^2 + 1210317^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-57516113121133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (57516113127133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28758056560566 + 28758056560567.
It is an arithmetic number, because the mean of its divisors is an integer number (28758056560567).
Almost surely, 257516113121133 is an apocalyptic number.
It is an amenable number.
57516113121133 is a deficient number, since it is larger than the sum of its proper divisors (1).
57516113121133 is an equidigital number, since it uses as much as digits as its factorization.
57516113121133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 56700, while the sum is 40.
The spelling of 57516113121133 in words is "fifty-seven trillion, five hundred sixteen billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •