Base | Representation |
---|---|
bin | 1010101110101000… |
… | …10101100110010001 |
3 | 112212102022001221021 |
4 | 11113110111212101 |
5 | 43244014311213 |
6 | 2351314555441 |
7 | 262510324165 |
oct | 52724254621 |
9 | 15772261837 |
10 | 5759916433 |
11 | 2496360517 |
12 | 1148b98b81 |
13 | 70a418b9b |
14 | 3c8d94ca5 |
15 | 23aa11d8d |
hex | 157515991 |
5759916433 has 2 divisors, whose sum is σ = 5759916434. Its totient is φ = 5759916432.
The previous prime is 5759916431. The next prime is 5759916439. The reversal of 5759916433 is 3346199575.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4975468369 + 784448064 = 70537^2 + 28008^2 .
It is a cyclic number.
It is not a de Polignac number, because 5759916433 - 21 = 5759916431 is a prime.
Together with 5759916431, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5759916431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2879958216 + 2879958217.
It is an arithmetic number, because the mean of its divisors is an integer number (2879958217).
Almost surely, 25759916433 is an apocalyptic number.
It is an amenable number.
5759916433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5759916433 is an equidigital number, since it uses as much as digits as its factorization.
5759916433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3061800, while the sum is 52.
The square root of 5759916433 is about 75894.1132960917. The cubic root of 5759916433 is about 1792.5532296562.
The spelling of 5759916433 in words is "five billion, seven hundred fifty-nine million, nine hundred sixteen thousand, four hundred thirty-three".
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