Base | Representation |
---|---|
bin | 101001111111111111101… |
… | …1010001101000010001111 |
3 | 202102211122022011112100011 |
4 | 1103333333122031002033 |
5 | 1224033412042401433 |
6 | 20135452125214051 |
7 | 1134021046413166 |
oct | 123777732150217 |
9 | 22384568145304 |
10 | 5772426137743 |
11 | 1926088082441 |
12 | 792899a01327 |
13 | 32b4504b64c5 |
14 | 15d55b9a83dd |
15 | a0249dc53cd |
hex | 53fff68d08f |
5772426137743 has 2 divisors, whose sum is σ = 5772426137744. Its totient is φ = 5772426137742.
The previous prime is 5772426137729. The next prime is 5772426137771. The reversal of 5772426137743 is 3477316242775.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5772426137743 - 25 = 5772426137711 is a prime.
It is a super-4 number, since 4×57724261377434 (a number of 52 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5772426131743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2886213068871 + 2886213068872.
It is an arithmetic number, because the mean of its divisors is an integer number (2886213068872).
Almost surely, 25772426137743 is an apocalyptic number.
5772426137743 is a deficient number, since it is larger than the sum of its proper divisors (1).
5772426137743 is an equidigital number, since it uses as much as digits as its factorization.
5772426137743 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41489280, while the sum is 58.
The spelling of 5772426137743 in words is "five trillion, seven hundred seventy-two billion, four hundred twenty-six million, one hundred thirty-seven thousand, seven hundred forty-three".
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