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57912018414113 is a prime number
BaseRepresentation
bin11010010101011101100010…
…10010010010101000100001
321121001100001010200000112002
431022232301102102220201
530042312303203222423
6323100225230413345
715125001542331143
oct1512566122225041
9247040033600462
1057912018414113
11174a83926a4676
1265b38a1961255
132641106718836
141042d57078c93
156a6657a47228
hex34abb1492a21

57912018414113 has 2 divisors, whose sum is σ = 57912018414114. Its totient is φ = 57912018414112.

The previous prime is 57912018414077. The next prime is 57912018414121. The reversal of 57912018414113 is 31141481021975.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30717222305344 + 27194796108769 = 5542312^2 + 5214863^2 .

It is a cyclic number.

It is not a de Polignac number, because 57912018414113 - 224 = 57912001636897 is a prime.

It is not a weakly prime, because it can be changed into another prime (57912018714113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28956009207056 + 28956009207057.

It is an arithmetic number, because the mean of its divisors is an integer number (28956009207057).

Almost surely, 257912018414113 is an apocalyptic number.

It is an amenable number.

57912018414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

57912018414113 is an equidigital number, since it uses as much as digits as its factorization.

57912018414113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 47.

The spelling of 57912018414113 in words is "fifty-seven trillion, nine hundred twelve billion, eighteen million, four hundred fourteen thousand, one hundred thirteen".