Base | Representation |
---|---|
bin | 11010010101011101100010… |
… | …10010010010101000100001 |
3 | 21121001100001010200000112002 |
4 | 31022232301102102220201 |
5 | 30042312303203222423 |
6 | 323100225230413345 |
7 | 15125001542331143 |
oct | 1512566122225041 |
9 | 247040033600462 |
10 | 57912018414113 |
11 | 174a83926a4676 |
12 | 65b38a1961255 |
13 | 2641106718836 |
14 | 1042d57078c93 |
15 | 6a6657a47228 |
hex | 34abb1492a21 |
57912018414113 has 2 divisors, whose sum is σ = 57912018414114. Its totient is φ = 57912018414112.
The previous prime is 57912018414077. The next prime is 57912018414121. The reversal of 57912018414113 is 31141481021975.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30717222305344 + 27194796108769 = 5542312^2 + 5214863^2 .
It is a cyclic number.
It is not a de Polignac number, because 57912018414113 - 224 = 57912001636897 is a prime.
It is not a weakly prime, because it can be changed into another prime (57912018714113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28956009207056 + 28956009207057.
It is an arithmetic number, because the mean of its divisors is an integer number (28956009207057).
Almost surely, 257912018414113 is an apocalyptic number.
It is an amenable number.
57912018414113 is a deficient number, since it is larger than the sum of its proper divisors (1).
57912018414113 is an equidigital number, since it uses as much as digits as its factorization.
57912018414113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 47.
The spelling of 57912018414113 in words is "fifty-seven trillion, nine hundred twelve billion, eighteen million, four hundred fourteen thousand, one hundred thirteen".
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