Base | Representation |
---|---|
bin | 101010010010000101001… |
… | …1001011110111110100101 |
3 | 202120112220001201112022112 |
4 | 1110210022121132332211 |
5 | 1230202432343013013 |
6 | 20205354113210405 |
7 | 1136564366134664 |
oct | 124441231367645 |
9 | 22515801645275 |
10 | 5811265204133 |
11 | 19405a8787914 |
12 | 79a318b60a05 |
13 | 331cccba21ac |
14 | 1613a3cd4ddb |
15 | a126e9dbba8 |
hex | 5490a65efa5 |
5811265204133 has 2 divisors, whose sum is σ = 5811265204134. Its totient is φ = 5811265204132.
The previous prime is 5811265204097. The next prime is 5811265204159. The reversal of 5811265204133 is 3314025621185.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5374969286404 + 436295917729 = 2318398^2 + 660527^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5811265204133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5811265284133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2905632602066 + 2905632602067.
It is an arithmetic number, because the mean of its divisors is an integer number (2905632602067).
Almost surely, 25811265204133 is an apocalyptic number.
It is an amenable number.
5811265204133 is a deficient number, since it is larger than the sum of its proper divisors (1).
5811265204133 is an equidigital number, since it uses as much as digits as its factorization.
5811265204133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 5811265204133 in words is "five trillion, eight hundred eleven billion, two hundred sixty-five million, two hundred four thousand, one hundred thirty-three".
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