Base | Representation |
---|---|
bin | 11010011011010111001100… |
… | …00100011010110110100001 |
3 | 21121202201101001201100011022 |
4 | 31031223212010122312201 |
5 | 30104123020430324441 |
6 | 323333320001455225 |
7 | 15145440053501630 |
oct | 1515534604326641 |
9 | 247681331640138 |
10 | 58114767433121 |
11 | 17576375192503 |
12 | 6627046041515 |
13 | 2657278425179 |
14 | 104caac2ad517 |
15 | 6aba724d584b |
hex | 34dae611ada1 |
58114767433121 has 32 divisors (see below), whose sum is σ = 67584906098688. Its totient is φ = 48938573053440.
The previous prime is 58114767433081. The next prime is 58114767433139. The reversal of 58114767433121 is 12133476741185.
58114767433121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 58114767433121 - 210 = 58114767432097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (58114767433321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2808416051 + ... + 2808436743.
It is an arithmetic number, because the mean of its divisors is an integer number (2112028315584).
Almost surely, 258114767433121 is an apocalyptic number.
It is an amenable number.
58114767433121 is a deficient number, since it is larger than the sum of its proper divisors (9470138665567).
58114767433121 is a wasteful number, since it uses less digits than its factorization.
58114767433121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28161.
The product of its digits is 3386880, while the sum is 53.
The spelling of 58114767433121 in words is "fifty-eight trillion, one hundred fourteen billion, seven hundred sixty-seven million, four hundred thirty-three thousand, one hundred twenty-one".
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