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5814451977053 is a prime number
BaseRepresentation
bin101010010011100100001…
…0110000011101101011101
3202120212010011012100221012
41110213020112003231131
51230230444201231203
620211042232545005
71140036353225066
oct124471026035535
922525104170835
105814451977053
111941993616545
1279aa68252165
133323ba18c345
141615c723956d
15a13a9675bd8
hex549c8583b5d

5814451977053 has 2 divisors, whose sum is σ = 5814451977054. Its totient is φ = 5814451977052.

The previous prime is 5814451977029. The next prime is 5814451977119. The reversal of 5814451977053 is 3507791544185.

5814451977053 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5374482433849 + 439969543204 = 2318293^2 + 663302^2 .

It is a cyclic number.

It is not a de Polignac number, because 5814451977053 - 222 = 5814447782749 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5814451976983 and 5814451977001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5814451970053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2907225988526 + 2907225988527.

It is an arithmetic number, because the mean of its divisors is an integer number (2907225988527).

Almost surely, 25814451977053 is an apocalyptic number.

It is an amenable number.

5814451977053 is a deficient number, since it is larger than the sum of its proper divisors (1).

5814451977053 is an equidigital number, since it uses as much as digits as its factorization.

5814451977053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21168000, while the sum is 59.

The spelling of 5814451977053 in words is "five trillion, eight hundred fourteen billion, four hundred fifty-one million, nine hundred seventy-seven thousand, fifty-three".