Base | Representation |
---|---|
bin | 110110011001000011… |
… | …010010010011101001 |
3 | 12120202011022210101121 |
4 | 312121003102103221 |
5 | 1424102000202223 |
6 | 42455113015241 |
7 | 4135156533616 |
oct | 663103222351 |
9 | 176664283347 |
10 | 58402350313 |
11 | 2284a67121a |
12 | b39a9b4521 |
13 | 5679768148 |
14 | 2b8061150d |
15 | 17bc36a15d |
hex | d990d24e9 |
58402350313 has 2 divisors, whose sum is σ = 58402350314. Its totient is φ = 58402350312.
The previous prime is 58402350301. The next prime is 58402350323. The reversal of 58402350313 is 31305320485.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51224363584 + 7177986729 = 226328^2 + 84723^2 .
It is a cyclic number.
It is not a de Polignac number, because 58402350313 - 213 = 58402342121 is a prime.
It is not a weakly prime, because it can be changed into another prime (58402350323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29201175156 + 29201175157.
It is an arithmetic number, because the mean of its divisors is an integer number (29201175157).
Almost surely, 258402350313 is an apocalyptic number.
It is an amenable number.
58402350313 is a deficient number, since it is larger than the sum of its proper divisors (1).
58402350313 is an equidigital number, since it uses as much as digits as its factorization.
58402350313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 58402350313 its reverse (31305320485), we get a palindrome (89707670798).
The spelling of 58402350313 in words is "fifty-eight billion, four hundred two million, three hundred fifty thousand, three hundred thirteen".
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