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58443213953 is a prime number
BaseRepresentation
bin110110011011011111…
…001010110010000001
312120212000012212202202
4312123133022302001
51424142430321303
642503132522545
74136164056605
oct663337126201
9176760185682
1058443213953
1122870741723
12b3b0620455
135685074b07
142b85c0b505
1517c0c3cc88
hexd9b7cac81

58443213953 has 2 divisors, whose sum is σ = 58443213954. Its totient is φ = 58443213952.

The previous prime is 58443213947. The next prime is 58443214069. The reversal of 58443213953 is 35931234485.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57653772544 + 789441409 = 240112^2 + 28097^2 .

It is a cyclic number.

It is not a de Polignac number, because 58443213953 - 24 = 58443213937 is a prime.

It is a super-2 number, since 2×584432139532 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 58443213898 and 58443213907.

It is not a weakly prime, because it can be changed into another prime (58443213253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29221606976 + 29221606977.

It is an arithmetic number, because the mean of its divisors is an integer number (29221606977).

Almost surely, 258443213953 is an apocalyptic number.

It is an amenable number.

58443213953 is a deficient number, since it is larger than the sum of its proper divisors (1).

58443213953 is an equidigital number, since it uses as much as digits as its factorization.

58443213953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1555200, while the sum is 47.

The spelling of 58443213953 in words is "fifty-eight billion, four hundred forty-three million, two hundred thirteen thousand, nine hundred fifty-three".