Base | Representation |
---|---|
bin | 110110111000001101… |
… | …000010100001100011 |
3 | 12122002120210012002011 |
4 | 312320031002201203 |
5 | 1431134300011203 |
6 | 43023023133351 |
7 | 4154134146154 |
oct | 667015024143 |
9 | 178076705064 |
10 | 58925000803 |
11 | 22a98699279 |
12 | b505a44257 |
13 | 5730b20ba6 |
14 | 2bcdbc192b |
15 | 17ed1a976d |
hex | db8342863 |
58925000803 has 2 divisors, whose sum is σ = 58925000804. Its totient is φ = 58925000802.
The previous prime is 58925000801. The next prime is 58925000807. The reversal of 58925000803 is 30800052985.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 58925000803 - 21 = 58925000801 is a prime.
It is a super-3 number, since 3×589250008033 (a number of 33 digits) contains 333 as substring.
Together with 58925000801, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (58925000801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29462500401 + 29462500402.
It is an arithmetic number, because the mean of its divisors is an integer number (29462500402).
Almost surely, 258925000803 is an apocalyptic number.
58925000803 is a deficient number, since it is larger than the sum of its proper divisors (1).
58925000803 is an equidigital number, since it uses as much as digits as its factorization.
58925000803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 58925000803 in words is "fifty-eight billion, nine hundred twenty-five million, eight hundred three", and thus it is an aban number.
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