590004973 has 2 divisors, whose sum is σ = 590004974. Its totient is φ = 590004972.

The previous prime is 590004937. The next prime is 590005001. The reversal of 590004973 is 379400095.

590004973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (590004937) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 352012644 + 237992329 = 18762^2 + 15427^2 .

It is a cyclic number.

It is not a de Polignac number, because 590004973 - 2¹⁷ = 589873901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (590004673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 295002486 + 295002487.

It is an arithmetic number, because the mean of its divisors is an integer number (295002487).

Almost surely, 2^590004973 is an apocalyptic number.

It is an amenable number.

590004973 is a deficient number, since it is larger than the sum of its proper divisors (1).

590004973 is an equidigital number, since it uses as much as digits as its factorization.

590004973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34020, while the sum is 37.

The square root of 590004973 is about 24290.0179703515. The cubic root of 590004973 is about 838.7230091194.

The spelling of 590004973 in words is "five hundred ninety million, four thousand, nine hundred seventy-three".