Base | Representation |
---|---|
bin | 101011000000100010011… |
… | …1010010011100001000001 |
3 | 202221002101220220220002011 |
4 | 1112001010322103201001 |
5 | 1233321242432244043 |
6 | 20323253515252521 |
7 | 1150025601430036 |
oct | 126010472234101 |
9 | 22832356826064 |
10 | 5911031134273 |
11 | 1979943a7a851 |
12 | 7b572044a141 |
13 | 33b53c059055 |
14 | 166149c2538d |
15 | a3b5d3dc59d |
hex | 56044e93841 |
5911031134273 has 2 divisors, whose sum is σ = 5911031134274. Its totient is φ = 5911031134272.
The previous prime is 5911031134271. The next prime is 5911031134429. The reversal of 5911031134273 is 3724311301195.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5905833156864 + 5197977409 = 2430192^2 + 72097^2 .
It is a cyclic number.
It is not a de Polignac number, because 5911031134273 - 21 = 5911031134271 is a prime.
Together with 5911031134271, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5911031134271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2955515567136 + 2955515567137.
It is an arithmetic number, because the mean of its divisors is an integer number (2955515567137).
Almost surely, 25911031134273 is an apocalyptic number.
It is an amenable number.
5911031134273 is a deficient number, since it is larger than the sum of its proper divisors (1).
5911031134273 is an equidigital number, since it uses as much as digits as its factorization.
5911031134273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 40.
The spelling of 5911031134273 in words is "five trillion, nine hundred eleven billion, thirty-one million, one hundred thirty-four thousand, two hundred seventy-three".
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