Base | Representation |
---|---|
bin | 101011000001011100111… |
… | …1010011100001110110011 |
3 | 202221021110201121002122122 |
4 | 1112002321322130032303 |
5 | 1233334302442313433 |
6 | 20324220400424455 |
7 | 1150125335413412 |
oct | 126027172341663 |
9 | 22837421532578 |
10 | 5912994104243 |
11 | 197a761025186 |
12 | 7b5b8991812b |
13 | 33b792939645 |
14 | 166294801479 |
15 | a3c258d8198 |
hex | 560b9e9c3b3 |
5912994104243 has 2 divisors, whose sum is σ = 5912994104244. Its totient is φ = 5912994104242.
The previous prime is 5912994104239. The next prime is 5912994104261. The reversal of 5912994104243 is 3424014992195.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5912994104243 - 22 = 5912994104239 is a prime.
It is not a weakly prime, because it can be changed into another prime (5912994104203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2956497052121 + 2956497052122.
It is an arithmetic number, because the mean of its divisors is an integer number (2956497052122).
Almost surely, 25912994104243 is an apocalyptic number.
5912994104243 is a deficient number, since it is larger than the sum of its proper divisors (1).
5912994104243 is an equidigital number, since it uses as much as digits as its factorization.
5912994104243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2799360, while the sum is 53.
The spelling of 5912994104243 in words is "five trillion, nine hundred twelve billion, nine hundred ninety-four million, one hundred four thousand, two hundred forty-three".
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