Base | Representation |
---|---|
bin | 110111001011101001… |
… | …110100010101111101 |
3 | 12122221022210111212221 |
4 | 313023221310111331 |
5 | 1432321313440442 |
6 | 43115241125341 |
7 | 4165205561563 |
oct | 671351642575 |
9 | 178838714787 |
10 | 59251311997 |
11 | 23145903749 |
12 | b597189851 |
13 | 5783601937 |
14 | 2c21283a33 |
15 | 181bb64467 |
hex | dcba7457d |
59251311997 has 2 divisors, whose sum is σ = 59251311998. Its totient is φ = 59251311996.
The previous prime is 59251311971. The next prime is 59251312013. The reversal of 59251311997 is 79911315295.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47899261881 + 11352050116 = 218859^2 + 106546^2 .
It is a cyclic number.
It is not a de Polignac number, because 59251311997 - 27 = 59251311869 is a prime.
It is a super-2 number, since 2×592513119972 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (59251311937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29625655998 + 29625655999.
It is an arithmetic number, because the mean of its divisors is an integer number (29625655999).
Almost surely, 259251311997 is an apocalyptic number.
It is an amenable number.
59251311997 is a deficient number, since it is larger than the sum of its proper divisors (1).
59251311997 is an equidigital number, since it uses as much as digits as its factorization.
59251311997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 765450, while the sum is 52.
The spelling of 59251311997 in words is "fifty-nine billion, two hundred fifty-one million, three hundred eleven thousand, nine hundred ninety-seven".
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