Base | Representation |
---|---|
bin | 1011000011010001… |
… | …10000001100110001 |
3 | 120022111001200102021 |
4 | 11201220300030301 |
5 | 44122324243213 |
6 | 2420421351441 |
7 | 300012003655 |
oct | 54150601461 |
9 | 16274050367 |
10 | 5933040433 |
11 | 2575057101 |
12 | 1196b68581 |
13 | 737253118 |
14 | 403d7ca65 |
15 | 24ad0cd8d |
hex | 161a30331 |
5933040433 has 2 divisors, whose sum is σ = 5933040434. Its totient is φ = 5933040432.
The previous prime is 5933040403. The next prime is 5933040461. The reversal of 5933040433 is 3340403395.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4781999104 + 1151041329 = 69152^2 + 33927^2 .
It is a cyclic number.
It is not a de Polignac number, because 5933040433 - 25 = 5933040401 is a prime.
It is a super-2 number, since 2×59330404332 = 70401937559225654978, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5933040403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2966520216 + 2966520217.
It is an arithmetic number, because the mean of its divisors is an integer number (2966520217).
Almost surely, 25933040433 is an apocalyptic number.
It is an amenable number.
5933040433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5933040433 is an equidigital number, since it uses as much as digits as its factorization.
5933040433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 34.
The square root of 5933040433 is about 77026.2321095872. The cubic root of 5933040433 is about 1810.3356451503.
The spelling of 5933040433 in words is "five billion, nine hundred thirty-three million, forty thousand, four hundred thirty-three".
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