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59403127313 is a prime number
BaseRepresentation
bin110111010100101100…
…111100101000010001
312200022220110112100102
4313110230330220101
51433124200033223
643142303102145
74202031152045
oct672454745021
9180286415312
1059403127313
1123213575852
12b619ba1955
1357a8bb7b9a
142c374c2025
15182a151928
hexdd4b3ca11

59403127313 has 2 divisors, whose sum is σ = 59403127314. Its totient is φ = 59403127312.

The previous prime is 59403127219. The next prime is 59403127339. The reversal of 59403127313 is 31372130495.

59403127313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39596224144 + 19806903169 = 198988^2 + 140737^2 .

It is a cyclic number.

It is not a de Polignac number, because 59403127313 - 214 = 59403110929 is a prime.

It is not a weakly prime, because it can be changed into another prime (59403127363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29701563656 + 29701563657.

It is an arithmetic number, because the mean of its divisors is an integer number (29701563657).

Almost surely, 259403127313 is an apocalyptic number.

It is an amenable number.

59403127313 is a deficient number, since it is larger than the sum of its proper divisors (1).

59403127313 is an equidigital number, since it uses as much as digits as its factorization.

59403127313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 38.

The spelling of 59403127313 in words is "fifty-nine billion, four hundred three million, one hundred twenty-seven thousand, three hundred thirteen".