Base | Representation |
---|---|
bin | 101011001111010110100… |
… | …1100000001100000111111 |
3 | 210001010112010001001122022 |
4 | 1112132231030001200333 |
5 | 1234331421404140141 |
6 | 20350034441110355 |
7 | 1152233151160013 |
oct | 126365514014077 |
9 | 23033463031568 |
10 | 5942845380671 |
11 | 199138a318a71 |
12 | 7bb91aa883bb |
13 | 34153c25b814 |
14 | 1678c71b4543 |
15 | a48c1435b4b |
hex | 567ad30183f |
5942845380671 has 2 divisors, whose sum is σ = 5942845380672. Its totient is φ = 5942845380670.
The previous prime is 5942845380611. The next prime is 5942845380691. The reversal of 5942845380671 is 1760835482495.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5942845380671 is a prime.
It is a super-2 number, since 2×59428453806712 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5942845380611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2971422690335 + 2971422690336.
It is an arithmetic number, because the mean of its divisors is an integer number (2971422690336).
It is a 2-persistent number, because it is pandigital, and so is 2⋅5942845380671 = 11885690761342, but 3⋅5942845380671 = 17828536142013 is not.
Almost surely, 25942845380671 is an apocalyptic number.
5942845380671 is a deficient number, since it is larger than the sum of its proper divisors (1).
5942845380671 is an equidigital number, since it uses as much as digits as its factorization.
5942845380671 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58060800, while the sum is 62.
The spelling of 5942845380671 in words is "five trillion, nine hundred forty-two billion, eight hundred forty-five million, three hundred eighty thousand, six hundred seventy-one".
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