Search a number
-
+
5946135493 is a prime number
BaseRepresentation
bin1011000100110101…
…01101001111000101
3120100101200222110111
411202122231033011
544134202313433
62422010153021
7300231213664
oct54232551705
916311628414
105946135493
112581490671
12119b422771
13739b8968c
144059caddb
1524c047dcd
hex1626ad3c5

5946135493 has 2 divisors, whose sum is σ = 5946135494. Its totient is φ = 5946135492.

The previous prime is 5946135469. The next prime is 5946135499. The reversal of 5946135493 is 3945316495.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3363768004 + 2582367489 = 57998^2 + 50817^2 .

It is a cyclic number.

It is not a de Polignac number, because 5946135493 - 29 = 5946134981 is a prime.

It is a super-2 number, since 2×59461354932 = 70713054602228706098, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5946135499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2973067746 + 2973067747.

It is an arithmetic number, because the mean of its divisors is an integer number (2973067747).

Almost surely, 25946135493 is an apocalyptic number.

It is an amenable number.

5946135493 is a deficient number, since it is larger than the sum of its proper divisors (1).

5946135493 is an equidigital number, since it uses as much as digits as its factorization.

5946135493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1749600, while the sum is 49.

The square root of 5946135493 is about 77111.1891556602. The cubic root of 5946135493 is about 1811.6665554624. Note that the first 3 decimals are identical.

The spelling of 5946135493 in words is "five billion, nine hundred forty-six million, one hundred thirty-five thousand, four hundred ninety-three".