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59473620053 is a prime number
BaseRepresentation
bin110111011000111001…
…110110110001010101
312200111211002221012122
4313120321312301111
51433300221320203
643153302025325
74203545300201
oct673071666125
9180454087178
1059473620053
112324a343011
12b639718245
1357ba699a73
142c429d1b01
151831428538
hexdd8e76c55

59473620053 has 2 divisors, whose sum is σ = 59473620054. Its totient is φ = 59473620052.

The previous prime is 59473620047. The next prime is 59473620071. The reversal of 59473620053 is 35002637495.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56909919364 + 2563700689 = 238558^2 + 50633^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-59473620053 is a prime.

It is a super-2 number, since 2×594736200532 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 59473619986 and 59473620013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (59473620043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29736810026 + 29736810027.

It is an arithmetic number, because the mean of its divisors is an integer number (29736810027).

Almost surely, 259473620053 is an apocalyptic number.

It is an amenable number.

59473620053 is a deficient number, since it is larger than the sum of its proper divisors (1).

59473620053 is an equidigital number, since it uses as much as digits as its factorization.

59473620053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 680400, while the sum is 44.

The spelling of 59473620053 in words is "fifty-nine billion, four hundred seventy-three million, six hundred twenty thousand, fifty-three".