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5969113288597 is a prime number
BaseRepresentation
bin101011011011100101011…
…1000001000111110010101
3210010122022202202001011001
41112313022320020332111
51240244221000213342
620410101153343301
71154153122540654
oct126671270107625
923118282661131
105969113288597
1119a1539922a88
12804a2bb67b31
13343b673749c4
14168c99ac719b
15a540c5a98b7
hex56dcae08f95

5969113288597 has 2 divisors, whose sum is σ = 5969113288598. Its totient is φ = 5969113288596.

The previous prime is 5969113288447. The next prime is 5969113288673. The reversal of 5969113288597 is 7958823119695.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4491797016996 + 1477316271601 = 2119386^2 + 1215449^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5969113288597 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5969113286597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2984556644298 + 2984556644299.

It is an arithmetic number, because the mean of its divisors is an integer number (2984556644299).

Almost surely, 25969113288597 is an apocalyptic number.

It is an amenable number.

5969113288597 is a deficient number, since it is larger than the sum of its proper divisors (1).

5969113288597 is an equidigital number, since it uses as much as digits as its factorization.

5969113288597 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 293932800, while the sum is 73.

The spelling of 5969113288597 in words is "five trillion, nine hundred sixty-nine billion, one hundred thirteen million, two hundred eighty-eight thousand, five hundred ninety-seven".