Base | Representation |
---|---|
bin | 101011011101100000110… |
… | …1110111101000111110101 |
3 | 210011001000101211022121021 |
4 | 1112323001232331013311 |
5 | 1240331211220244414 |
6 | 20412024141421141 |
7 | 1154360552342035 |
oct | 126730156750765 |
9 | 23131011738537 |
10 | 5973254853109 |
11 | 19a3274707775 |
12 | 8057a6b6a7b1 |
13 | 3443774008ab |
14 | 16916db6b8c5 |
15 | a55a0e94c24 |
hex | 56ec1bbd1f5 |
5973254853109 has 2 divisors, whose sum is σ = 5973254853110. Its totient is φ = 5973254853108.
The previous prime is 5973254852977. The next prime is 5973254853133. The reversal of 5973254853109 is 9013584523795.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5879800528900 + 93454324209 = 2424830^2 + 305703^2 .
It is a cyclic number.
It is not a de Polignac number, because 5973254853109 - 215 = 5973254820341 is a prime.
It is a super-3 number, since 3×59732548531093 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5973254853169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2986627426554 + 2986627426555.
It is an arithmetic number, because the mean of its divisors is an integer number (2986627426555).
Almost surely, 25973254853109 is an apocalyptic number.
It is an amenable number.
5973254853109 is a deficient number, since it is larger than the sum of its proper divisors (1).
5973254853109 is an equidigital number, since it uses as much as digits as its factorization.
5973254853109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824000, while the sum is 61.
The spelling of 5973254853109 in words is "five trillion, nine hundred seventy-three billion, two hundred fifty-four million, eight hundred fifty-three thousand, one hundred nine".
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