Base | Representation |
---|---|
bin | 1011001000100011… |
… | …01000100000010101 |
3 | 120102120100212120021 |
4 | 11210101220200111 |
5 | 44220142430003 |
6 | 2425042305141 |
7 | 301060210264 |
oct | 54421504025 |
9 | 16376325507 |
10 | 5977311253 |
11 | 2598044461 |
12 | 11a99581b1 |
13 | 743483884 |
14 | 409bc45db |
15 | 24eb552bd |
hex | 164468815 |
5977311253 has 2 divisors, whose sum is σ = 5977311254. Its totient is φ = 5977311252.
The previous prime is 5977311217. The next prime is 5977311259. The reversal of 5977311253 is 3521137795.
5977311253 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4763346289 + 1213964964 = 69017^2 + 34842^2 .
It is a cyclic number.
It is not a de Polignac number, because 5977311253 - 213 = 5977303061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5977311259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2988655626 + 2988655627.
It is an arithmetic number, because the mean of its divisors is an integer number (2988655627).
Almost surely, 25977311253 is an apocalyptic number.
It is an amenable number.
5977311253 is a deficient number, since it is larger than the sum of its proper divisors (1).
5977311253 is an equidigital number, since it uses as much as digits as its factorization.
5977311253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 198450, while the sum is 43.
The square root of 5977311253 is about 77313.0729760498. The cubic root of 5977311253 is about 1814.8272446987.
The spelling of 5977311253 in words is "five billion, nine hundred seventy-seven million, three hundred eleven thousand, two hundred fifty-three".
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