Base | Representation |
---|---|
bin | 101011100100001001100… |
… | …0100110011100110011101 |
3 | 210012101210110221012211002 |
4 | 1113020103010303212131 |
5 | 1241044402114001121 |
6 | 20422342131440045 |
7 | 1155403640662235 |
oct | 127102304634635 |
9 | 23171713835732 |
10 | 5987504437661 |
11 | 19a931718552a |
12 | 808503156025 |
13 | 345808638026 |
14 | 169b22452cc5 |
15 | a5b36e78e0b |
hex | 5721313399d |
5987504437661 has 2 divisors, whose sum is σ = 5987504437662. Its totient is φ = 5987504437660.
The previous prime is 5987504437567. The next prime is 5987504437667. The reversal of 5987504437661 is 1667344057895.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5591423015161 + 396081422500 = 2364619^2 + 629350^2 .
It is a cyclic number.
It is not a de Polignac number, because 5987504437661 - 210 = 5987504436637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5987504437667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2993752218830 + 2993752218831.
It is an arithmetic number, because the mean of its divisors is an integer number (2993752218831).
Almost surely, 25987504437661 is an apocalyptic number.
It is an amenable number.
5987504437661 is a deficient number, since it is larger than the sum of its proper divisors (1).
5987504437661 is an equidigital number, since it uses as much as digits as its factorization.
5987504437661 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 152409600, while the sum is 65.
The spelling of 5987504437661 in words is "five trillion, nine hundred eighty-seven billion, five hundred four million, four hundred thirty-seven thousand, six hundred sixty-one".
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