Base | Representation |
---|---|
bin | 101011100110000110110… |
… | …0001110110000110000101 |
3 | 210012210122022120200111010 |
4 | 1113030031201312012011 |
5 | 1241132003311312203 |
6 | 20424315113232433 |
7 | 1155613032454320 |
oct | 127141541660605 |
9 | 23183568520433 |
10 | 5991706354053 |
11 | 1a00083040502 |
12 | 809296402719 |
13 | 3460280350a4 |
14 | 16a0005277b7 |
15 | a5cd0cd6303 |
hex | 5730d876185 |
5991706354053 has 32 divisors (see below), whose sum is σ = 9410352272640. Its totient is φ = 3319440929280.
The previous prime is 5991706354037. The next prime is 5991706354157. The reversal of 5991706354053 is 3504536071995.
5991706354053 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5991706354053 - 24 = 5991706354037 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 5991706353984 and 5991706354002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5991706374053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13502898 + ... + 13939571.
It is an arithmetic number, because the mean of its divisors is an integer number (294073508520).
Almost surely, 25991706354053 is an apocalyptic number.
It is an amenable number.
5991706354053 is a deficient number, since it is larger than the sum of its proper divisors (3418645918587).
5991706354053 is a wasteful number, since it uses less digits than its factorization.
5991706354053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27442797.
The product of its (nonzero) digits is 15309000, while the sum is 57.
The spelling of 5991706354053 in words is "five trillion, nine hundred ninety-one billion, seven hundred six million, three hundred fifty-four thousand, fifty-three".
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