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23183568520433 is a prime number
BaseRepresentation
bin1010100010101110110000…
…10111011100010011110001
310001002022211202021211002222
411101113120113130103301
511014314422020123213
6121150215004050425
74611646303660526
oct521273027342361
9101068752254088
1023183568520433
117429107043132
12272516a233a15
13cc227cb65a19
145a213ac6714d
152a30d0227808
hex1515d85dc4f1

23183568520433 has 2 divisors, whose sum is σ = 23183568520434. Its totient is φ = 23183568520432.

The previous prime is 23183568520429. The next prime is 23183568520447. The reversal of 23183568520433 is 33402586538132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13704263513329 + 9479305007104 = 3701927^2 + 3078848^2 .

It is a cyclic number.

It is not a de Polignac number, because 23183568520433 - 22 = 23183568520429 is a prime.

It is a super-2 number, since 2×231835685204332 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (23183568520633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11591784260216 + 11591784260217.

It is an arithmetic number, because the mean of its divisors is an integer number (11591784260217).

Almost surely, 223183568520433 is an apocalyptic number.

It is an amenable number.

23183568520433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23183568520433 is an equidigital number, since it uses as much as digits as its factorization.

23183568520433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12441600, while the sum is 53.

The spelling of 23183568520433 in words is "twenty-three trillion, one hundred eighty-three billion, five hundred sixty-eight million, five hundred twenty thousand, four hundred thirty-three".